3.8.57 \(\int x^2 \sqrt {c x^2} (a+b x) \, dx\) [757]

Optimal. Leaf size=35 \[ \frac {1}{4} a x^3 \sqrt {c x^2}+\frac {1}{5} b x^4 \sqrt {c x^2} \]

[Out]

1/4*a*x^3*(c*x^2)^(1/2)+1/5*b*x^4*(c*x^2)^(1/2)

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Rubi [A]
time = 0.01, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {15, 45} \begin {gather*} \frac {1}{4} a x^3 \sqrt {c x^2}+\frac {1}{5} b x^4 \sqrt {c x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2*Sqrt[c*x^2]*(a + b*x),x]

[Out]

(a*x^3*Sqrt[c*x^2])/4 + (b*x^4*Sqrt[c*x^2])/5

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int x^2 \sqrt {c x^2} (a+b x) \, dx &=\frac {\sqrt {c x^2} \int x^3 (a+b x) \, dx}{x}\\ &=\frac {\sqrt {c x^2} \int \left (a x^3+b x^4\right ) \, dx}{x}\\ &=\frac {1}{4} a x^3 \sqrt {c x^2}+\frac {1}{5} b x^4 \sqrt {c x^2}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 24, normalized size = 0.69 \begin {gather*} \frac {1}{20} x^3 \sqrt {c x^2} (5 a+4 b x) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2*Sqrt[c*x^2]*(a + b*x),x]

[Out]

(x^3*Sqrt[c*x^2]*(5*a + 4*b*x))/20

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Mathics [A]
time = 1.72, size = 19, normalized size = 0.54 \begin {gather*} x^3 \left (\frac {a}{4}+\frac {b x}{5}\right ) \sqrt {c x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

mathics('Integrate[x^2*Sqrt[c*x^2]*(a + b*x),x]')

[Out]

x ^ 3 (a / 4 + b x / 5) Sqrt[c x ^ 2]

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Maple [A]
time = 0.02, size = 21, normalized size = 0.60

method	result	size
gosper	\(\frac {x^{3} \left (4 b x +5 a \right ) \sqrt {c \,x^{2}}}{20}\)	\(21\)
default	\(\frac {x^{3} \left (4 b x +5 a \right ) \sqrt {c \,x^{2}}}{20}\)	\(21\)
risch	\(\frac {a \,x^{3} \sqrt {c \,x^{2}}}{4}+\frac {b \,x^{4} \sqrt {c \,x^{2}}}{5}\)	\(28\)
trager	\(\frac {\left (4 b \,x^{4}+5 a \,x^{3}+4 b \,x^{3}+5 a \,x^{2}+4 x^{2} b +5 a x +4 b x +5 a +4 b \right ) \left (-1+x \right ) \sqrt {c \,x^{2}}}{20 x}\)	\(61\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(b*x+a)*(c*x^2)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/20*x^3*(4*b*x+5*a)*(c*x^2)^(1/2)

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Maxima [A]
time = 0.26, size = 31, normalized size = 0.89 \begin {gather*} \frac {\left (c x^{2}\right )^{\frac {3}{2}} b x^{2}}{5 \, c} + \frac {\left (c x^{2}\right )^{\frac {3}{2}} a x}{4 \, c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)*(c*x^2)^(1/2),x, algorithm="maxima")

[Out]

1/5*(c*x^2)^(3/2)*b*x^2/c + 1/4*(c*x^2)^(3/2)*a*x/c

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Fricas [A]
time = 0.30, size = 22, normalized size = 0.63 \begin {gather*} \frac {1}{20} \, {\left (4 \, b x^{4} + 5 \, a x^{3}\right )} \sqrt {c x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)*(c*x^2)^(1/2),x, algorithm="fricas")

[Out]

1/20*(4*b*x^4 + 5*a*x^3)*sqrt(c*x^2)

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Sympy [A]
time = 0.12, size = 29, normalized size = 0.83 \begin {gather*} \frac {a x^{3} \sqrt {c x^{2}}}{4} + \frac {b x^{4} \sqrt {c x^{2}}}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(b*x+a)*(c*x**2)**(1/2),x)

[Out]

a*x**3*sqrt(c*x**2)/4 + b*x**4*sqrt(c*x**2)/5

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Giac [A]
time = 0.00, size = 25, normalized size = 0.71 \begin {gather*} \sqrt {c} \left (\frac {1}{4} a x^{4} \mathrm {sign}\left (x\right )+\frac {1}{5} b x^{5} \mathrm {sign}\left (x\right )\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)*(c*x^2)^(1/2),x)

[Out]

1/20*(4*b*x^5*sgn(x) + 5*a*x^4*sgn(x))*sqrt(c)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int x^2\,\sqrt {c\,x^2}\,\left (a+b\,x\right ) \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(c*x^2)^(1/2)*(a + b*x),x)

[Out]

int(x^2*(c*x^2)^(1/2)*(a + b*x), x)

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